/* Routines for time-delayed actions. * * (C) 2003 Anope Team * Contact us at info@anope.org * * Please read COPYING and README for furhter details. * * Based on the original code of Epona by Lara. * Based on the original code of Services by Andy Church. * * $Id: timeout.c 420 2004-10-23 23:42:15Z trystan $ * */ #include "services.h" #include "timeout.h" static Timeout *timeouts = NULL; /*************************************************************************/ #ifdef DEBUG_COMMANDS /* Send the timeout list to the given user. */ void send_timeout_list(User * u) { Timeout *to, *last; notice(s_OperServ, u->nick, "Now: %ld", time(NULL)); for (to = timeouts, last = NULL; to; last = to, to = to->next) { notice(s_OperServ, u->nick, "%p: %ld: %p (%p)", to, to->timeout, to->code, to->data); if (to->prev != last) notice(s_OperServ, u->nick, " to->prev incorrect! expected=%p seen=%p", last, to->prev); } } #endif /* DEBUG_COMMANDS */ /*************************************************************************/ /* Check the timeout list for any pending actions. */ void check_timeouts(void) { Timeout *to, *to2; time_t t = time(NULL); if (debug >= 2) alog("debug: Checking timeouts at %ld", (long int) t); to = timeouts; while (to) { if (t < to->timeout) { to = to->next; continue; } if (debug >= 4) { alog("debug: Running timeout %p (code=%p repeat=%d)", to, to->code, to->repeat); } to->code(to); if (to->repeat) { to = to->next; continue; } to2 = to->next; if (to->next) to->next->prev = to->prev; if (to->prev) to->prev->next = to->next; else timeouts = to->next; free(to); to = to2; } if (debug >= 2) alog("debug: Finished timeout list"); } /*************************************************************************/ /* Add a timeout to the list to be triggered in `delay' seconds. If * `repeat' is nonzero, do not delete the timeout after it is triggered. * This must maintain the property that timeouts added from within a * timeout routine do not get checked during that run of the timeout list. */ Timeout *add_timeout(int delay, void (*code) (Timeout *), int repeat) { Timeout *t = scalloc(sizeof(Timeout), 1); t->settime = time(NULL); t->timeout = t->settime + delay; t->code = code; t->repeat = repeat; t->next = timeouts; t->prev = NULL; if (timeouts) timeouts->prev = t; timeouts = t; return t; } /*************************************************************************/ /* Remove a timeout from the list (if it's there). */ void del_timeout(Timeout * t) { Timeout *ptr; for (ptr = timeouts; ptr; ptr = ptr->next) { if (ptr == t) break; } if (!ptr) return; if (t->prev) t->prev->next = t->next; else timeouts = t->next; if (t->next) t->next->prev = t->prev; free(t); } /*************************************************************************/