/***********************************************************************
**                                                                    **
**   Function    :  patmat                                            **
**                                                                    **
**   Purpose     :  Pattern Matching                                  **
**                                                                    **
**   Usage       :  Pass two string pointers as parameters.The first  **
**                  being a raw string & the second a pattern the raw **
**                  string is to be matched against.If the raw string **
**                  matches the pattern,then the function returns a   **
**                  1,else it returns a 0.                            **
**                                                                    **
**                  e.g  patmat("abcdefghi","*ghi") returns a 1.      **
**                       patmat("abcdefghi","??c??f*") returns a 1.   **
**                       patmat("abcdefghi","*dh*") returns a 0.      **
**                       patmat("abcdefghi","*def") returns a 0.      **
**                                                                    **
**                  The asterisk is a wild card to allow any charac-  **
**                  ters from its first appearance to the next spec-  **
**                  ific character.The character ? is a wild card     **
**                  for only one character in the position it appears.**
**                  Combinations such as "*?" or "?*" or "**" are     **
**                  illegal for obvious reasons & the functions may   **
**                  goof,though I think it will still work.           **
**                                                                    **
**   Author      :  Sreenath Chary              Nov 29 1988           **
**                                                                    **
**   Logic       :  The only simple way I could devise is to use      **
**                  recursion.Each character in the pattern is        **
**                  taken & compared with the character in the raw    **
**                  string.If it matches then the remaining amount    **
**                  of the string & the remaining amount of the       **
**                  pattern are passed as parameters to patmat again  **
**                  until the end of the pattern.If at any stage      **
**                  the pattern does not match,then we go back one    **
**                  level & at this level if the previous character   **
**                  was a asterisk in the pattern,we hunt again from  **
**                  where we left off,otherwise we return back one    **
**                  more level with a not found & the process goes    **
**                  on till the first level call.                     **
**                                                                    **
**                  Only one character at a time is considered,except **
**                  when the character is an asterisk.You'll get the  **
**                  logic as the program unfolds.                     **
**                                                                    **
**                                                                    **
**   This program is dedicated to the Public Domain.                  **
**                                                                    **
***********************************************************************/

#include <stddef.h>
#include <string.h>

int patmat(char *raw, char *pat)
{
    int i;

    if (*pat == '\0' && *raw == '\0')
    {
        /* if it is the end of both strings, then match */
        return 1;
    }
    if (*pat == '\0')
    {
        /* if it is the end of only pat then mismatch */
        return 0;
    }

    /* if pattern is `*' */

    if (*pat == '*')
    {
        if (*(pat + 1) == '\0')
        {
            /* if pat is just `*' then match */
            return 1;
        }
        else
        {
            /* else hunt for match or wild card */
            for (i = 0; i <= strlen(raw); i++)
            {
                if (*(raw + i) == *(pat + 1) || *(pat + 1) == '?')
                {
                    /* if found, match rest of pattern */
                    if (patmat(raw + i + 1, pat + 2) == 1)
                    {
                        return 1;
                    }
                }
            }
        }
    }
    else
    {
        if (*raw == '\0')
        {
            /* we've reached the end of raw; return a mismatch */
            return 0;
        }

        if (*pat == '?' || *pat == *raw)
        {
            /* if chars match then try and match rest of it */
            if (patmat(raw + 1, pat + 1) == 1)
            {
                return 1;
            }
        }
    }

    /* fell through; no match found */
    return 0;
}